Similar to electron diffraction, neutron diffraction microscope is also used for the determination of the structure of molecules. If the wavelength used here is 800 pm, calculate the characteristic velocity associated with the neutron.

Asked by Abhisek | 1 year ago |  91

##### Solution :-

From de Broglie’s equation,

$$\lambda =\dfrac{h}{m\nu }\\\nu=\dfrac{h}{m\lambda}$$

Where,

v denotes the velocity of the neutron

h is Planck’s constant

m is the mass of the neutron

λ is the wavelength

Substituting the values in the expression of velocity (v),

$$E=\dfrac{(6.626\times 10^{-34})}{(1.67493\times 10^{-27})(800\times 10^{-12}m)}$$

$$=4.94\times 10^{2}\, J \\$$

$$=494\, ms^{-1}$$

Therefore, the velocity associated with the neutron is 494 ms–1

Answered by Pragya Singh | 1 year ago

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