Indicate the number of unpaired electrons in:

(a) P

(b) Si

(c) Cr

(d) Fe

(e) Kr

Asked by Abhisek | 1 year ago |  151

##### Solution :-

(a) Phosphorus (P):

The atomic number of phosphorus is 15

Electronic configuration of Phosphorus:

1s 2 2s 2 2p 6 3s 2 3p 3

This can be represented as follows:

From the diagram, it can be observed that phosphorus has three unpaired electrons.

(b) Silicon (Si):

The atomic number of Silicon is 14

Electronic configuration of Silicon:

1s 2 2s 2 2p 6 3s 2 3p 2

This can be represented as follows:

From the diagram, it can be observed that silicon has two unpaired electrons.

(c) Chromium (Cr):

The atomic number of Cr is 24

Electronic configuration of Chromium:

1s 2 2s2 2p 6 3s 2 3p 6 4s 1 3d 5

This can be represented as follows:

From the diagram, it can be observed that chromium has six unpaired electrons.

(d) Iron (Fe):

The atomic number of iron is 26

Electronic configuration of Fe:

1s 2 2s2 2p 6 3s 2 3p 6 4s 2 3d 6

This can be represented as follows:

From the diagram, it can be observed that krypton has no unpaired electrons.

Answered by Pragya Singh | 1 year ago

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