A battery of 9 V is connected in series with resistors of 0.2 Ω, 0.3 Ω, 0.4 Ω, 0.5 Ω, and 12 Ω, respectively. How much current would flow through the 12 Ω resistor?

Asked by Vishal kumar | 1 year ago |  206

##### Solution :-

In series connection, there is no division of current. The current flowing across all the resistors is the same. To calculate the amount of current flowing across the resistors, we use Ohm’s law. But first, let us find out the equivalent resistance as follows:

R = 0.2 Ω + 0.3 Ω + 0.4 Ω + 0.5 Ω + 12 Ω = 13.4 Ω

Now, using Ohm’s law,

$$I=\frac{V}{R}=\frac{9V}{13.4\,\Omega}=0.671\,A$$

The current flowing across the 12 Ω is 0.671 A.

Answered by Shivani Kumari | 1 year ago

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