Energy of an electron in the ground state of the hydrogen atom is –2.18×10–18J. Calculate the ionization enthalpy of atomic hydrogen in terms of J mol–1.

Asked by Pragya Singh | 1 year ago |  67

##### Solution :-

Here it is given that, electron of hydrogen is having

$$-2.18 \times 10^{-18} J$$ in ground state.

Thus, $$-2.18 \times10^{-18} J$$

amount of energy will be required to expel an electron from ground state in H(hydrogen) – atom.

∴ For Hydrogen atom the Ionization of enthalpy

$$-2.18 \times10^{-18} J$$

Thus, ionization enthalpy of a Hydrogen atom in $$J\;mol^{-1}$$

$$-2.18 \times 10^{-18} \times 6.02 \times 10^{23}J\;mol^{-1}$$

Answered by Abhisek | 1 year ago

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