Energy of an electron in the ground state of the hydrogen atom is –2.18×10–18J. Calculate the ionization enthalpy of atomic hydrogen in terms of J mol–1.

Asked by Pragya Singh | 1 year ago |  67

1 Answer

Solution :-

Here it is given that, electron of hydrogen is having 

\( -2.18 \times 10^{-18} J\) in ground state.

Thus, \( -2.18 \times10^{-18} J\)

amount of energy will be required to expel an electron from ground state in H(hydrogen) – atom.

∴ For Hydrogen atom the Ionization of enthalpy 

\( -2.18 \times10^{-18} J\)

Thus, ionization enthalpy of a Hydrogen atom in \( J\;mol^{-1}\)

\( -2.18 \times 10^{-18} \times 6.02 \times 10^{23}J\;mol^{-1}\)

Answered by Abhisek | 1 year ago

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