Explain the formation of H2 molecule on the basis of valence bond theory.

Asked by Pragya Singh | 1 year ago |  69

1 Answer

Solution :-

Assuming 2 H- atoms X and Y with nuclei NX and NY and electrons eX and eY, respectively.

When X and Y are far for each other then there is no interaction between them. As soon as they come closer, the attractive force and repulsive force becomes active.

The repulsive forces are:

(i) Between electrons of both the atoms i.e. eX and eY.

(ii) Between nuclei of both the atoms i.e. NX and NY.

Explain the formation of H2 molecule on the basis of Valence Bond Theory. -  Sarthaks eConnect | Largest Online Education Community

The attractive forces are:

(i) Between the electron and nucleus of the same atom i.e. NX – eX and NY -eY.

(ii) Between the electron of one atom and nucleus of other atom i.e. NX–eY and NY–eX.

The repulsive force pushes the 2 atoms apart whereas the attractive force tend to bring them together.

The values of repulsive forces are less than that of attractive forces. Thus, 2 atoms approach each other. Thus, there is a decrease in potential energy. At the end a stage is reached when the repulsive forces balance the attractive forces and the system achieves the minimum energy,which leads to formation of H2 molecule.

Answered by Abhisek | 1 year ago

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