Initial pressure, P_{1} = 1.2bar

Initial volume, V_{1} = 120mL^{ }

Final volume, V_{2} = 180mL

As the temperature remains the same, final pressure (P_{2}) can be calculated with the help of Boyle’s law.

According to the Boyle’s law,

P_{1}V_{1} = P_{2}V_{2}

P_{2 }=\( \dfrac{P_{1}V_{1}}{V_{2}}\)

=\( \dfrac{1.2 \; \times \; 120}{180}\)

= 0.8bar

Therefore, the min pressure required is 0.8bar.

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