At 0°C , the density of certain oxide of a gas at 2 bar is same as that of dinitrogen at 5 bar. What is the molecular mass of the oxide?

Asked by Pragya Singh | 1 year ago |  106

1 Answer

Solution :-

Density (d) of the substance at temp (T) can be given by,

d = \( \dfrac{Mp}{RT}\)

Now, density of oxide (d1) is as given,

\( d_{1}= \dfrac{M_{1}p_{1}}{RT}\)

Where, M= mass of the oxide

p= pressure of the oxide

Density of dinitrogen gas (d2) is as given,

\( d_{2}= \dfrac{M_{1}p_{2}}{RT}\)

Where, M= mass of the oxide

p= pressure of the oxide

Acc to the question,

d= d2

Therefore, \( M_{1}p_{1} = M_{2}p_{2}\)

Given:

\( p_{1}\)​ = 2 bar

\( p_{2}\)​ = 5 bar

Molecular mass of nitrogen, \( M_{2}\)​ = 28g/mol

Now, \( M_{1}\)

\( \dfrac{M_{ 2 }p_{2}}{p_{ 1 }}\)

= \( \dfrac{ 28 × 5 }{ 2 }\)

= 70g/mol

Therefore, the molecular mass of the oxide is 70g/mol.

Answered by Pragya Singh | 1 year ago

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