At 0°C , the density of certain oxide of a gas at 2 bar is same as that of dinitrogen at 5 bar. What is the molecular mass of the oxide?

Asked by Pragya Singh | 1 year ago |  106

##### Solution :-

Density (d) of the substance at temp (T) can be given by,

d = $$\dfrac{Mp}{RT}$$

Now, density of oxide (d1) is as given,

$$d_{1}= \dfrac{M_{1}p_{1}}{RT}$$

Where, M= mass of the oxide

p= pressure of the oxide

Density of dinitrogen gas (d2) is as given,

$$d_{2}= \dfrac{M_{1}p_{2}}{RT}$$

Where, M= mass of the oxide

p= pressure of the oxide

Acc to the question,

d= d2

Therefore, $$M_{1}p_{1} = M_{2}p_{2}$$

Given:

$$p_{1}$$​ = 2 bar

$$p_{2}$$​ = 5 bar

Molecular mass of nitrogen, $$M_{2}$$​ = 28g/mol

Now, $$M_{1}$$

$$\dfrac{M_{ 2 }p_{2}}{p_{ 1 }}$$

= $$\dfrac{ 28 × 5 }{ 2 }$$

= 70g/mol

Therefore, the molecular mass of the oxide is 70g/mol.

Answered by Pragya Singh | 1 year ago

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