What would be the SI units for the quantity \(\dfrac{pV^2 T^2}{n}\)

Asked by Pragya Singh | 1 year ago |  131

1 Answer

Solution :-

SI unit of pressure, p = \( Nm^{ -2 }\)

SI unit of volume, V = \( m^{ 3 }\)

SI unit of temp, T = K

SI unit of number of moles, n = mol

Hence, SI unit of \( \dfrac{ pV^{ 2 }T^{ 2 } }{ n }\)​ is,

\( \dfrac{(Nm^{ -2 }) \; (m^{3})^{2} \; (K)^{2}}{mol}\)

=\( Nm^{ 4 }K^{ 2 }mol^{ -1 }\)

Answered by Abhisek | 1 year ago

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