$$\Delta U^{\Theta }$$of combustion of methane is – X kJ mol–1. The value of $$= \Delta H^{\Theta }$$is

(i) $$= \Delta U^{\Theta }$$

(ii) $$> \Delta U^{\Theta }$$

(iii) $$< \Delta U^{\Theta }$$

(iv) 0

Asked by Abhisek | 1 year ago |  85

##### Solution :-

Right answer is (iii) $$< \Delta U^{\Theta }$$

Reason:

$$\Delta H^{\Theta } = \Delta U^{\Theta }$$

$$+ \Delta n_{g}RT ; \Delta U^{\Theta }$$

$$= – Y kJ mol^{-1}$$

$$\Delta H^{\Theta } = ( – Y) + \Delta n_{g}RT \Rightarrow \Delta H^{\Theta } < \Delta U^{\Theta }$$

Answered by Pragya Singh | 1 year ago

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