A reaction, A + B → C + D + q  is found to have a positive entropy change. The reaction will be

(i) possible at high temperature

(ii) possible only at low temperature

(iii) not possible at any temperature

(iv) possible at any temperature

Asked by Abhisek | 1 year ago |  78

##### Solution :-

Right answer is (iv) possible at any temperature

$$\Delta G$$ should be –ve, for spontaneous reaction to occur

$$\Delta G = \Delta H – T\Delta S$$

As per given in question,

$$\Delta H$$ is –ve ( as heat is evolved)

$$\Delta S$$ is +ve

Therefore, $$\Delta G$$ is negative

So, the reaction will be possible at any temperature.

Answered by Pragya Singh | 1 year ago

### Related Questions

#### Calculate the entropy change in surroundings when 1.00 mol of H2O(l) is formed under standard conditions.

Calculate the entropy change in surroundings when 1.00 mol of $$H_2O$$(l) is formed under standard conditions. $$Δ_f H^ Θ= –286 kJ mol^{–1}.$$

#### Comment on the thermodynamic stability of NO(g), given,

Comment on the thermodynamic stability of NO(g), given,

($$\dfrac{1}{2}$$)N2(g) + ($$\dfrac{1}{2}$$)O2(g) → NO(g)$$\Delta _{r}H^{\Theta } = 90kJmol^{-1}$$

NO(g) + ($$\dfrac{1}{2}$$)O2(g) → NO2(g)$$\Delta _{r}H^{\Theta } = -74kJmol^{-1}$$

#### The equilibrium constant for a reaction is 10. What will be the value of ∆G0? R = 8.314 JK–1 mol–1, T = 300 K.

The equilibrium constant for a reaction is 10. What will be the value of ∆G0? R = 8.314 JK–1 mol–1, T = 300 K.

#### For the reaction 2A(g) + B(g)→ 2D(g)

For the reaction

2A(g) + B(g)→ 2D(g)

$$\Delta U^{\Theta } = -10.5 kJ \;and \;\Delta S^{\Theta } = -44.1JK^{-1}$$

Calculate $$\Delta G^{\Theta }$$ for the reaction, and predict whether the reaction may occur spontaneously.

What are the signs of $$\Delta S\; and \;\Delta H$$?