Calculate the number of kJ of heat necessary to raise the temperature of 60.0 g of aluminium from 35°C to 55°C. Molar heat capacity of Al is 24 J mol–1 K–1.

Asked by Abhisek | 1 year ago |  46

##### Solution :-

Expression of heat(q),

$$q = mCP\Delta T$$…….(a)

$$\Delta T$$ = Change in temperature

c = molar heat capacity

m = mass of substance

From (a)

$$q = ( \dfrac{60}{27}mol )(24mol^{-1}K^{-1})(20K)$$

q = 1066.67 J

= 1.067 KJ

Answered by Pragya Singh | 1 year ago

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