Enthalpy of combustion of carbon to CO2 is –393.5 kJ mol–1. Calculate the heat released upon formation of 35.2 g of CO2 from carbon and dioxygen gas.

Asked by Abhisek | 1 year ago |  87

Solution :-

Formation of carbon dioxide from di-oxygen and carbon gas is given as:

C(s) + O2(g) → CO2(g)

$$\Delta _{f}H = -393.5 kJ mol^{-1}$$

1 mole CO2 = 44g

Heat released during formation of 44g CO2

$$-393.5 kJ mol^{-1}$$

Therefore, heat released during formation of 35.2g of CO2  can be calculated as

=$$\dfrac{-393.5kJmol^{-1}}{44g}\times 35.2g$$

$$-314.8 kJ mol^{-1}$$

Answered by Pragya Singh | 1 year ago

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