An alkene ‘A’ contains three C – C, eight C – H σ bonds and one C – C π bond. ‘A’ on ozonolysis gives two moles of an aldehyde of molar mass 44 u. Write IUPAC name of ‘A’.

Asked by Pragya Singh | 1 year ago |  89

##### Solution :-

According to the given information, ‘A’ on ozonolysis gives two moles of an aldehyde of molar mass 44 u. The formation of two moles of an aldehyde indicates the presence of identical structural units on both sides of the double bond containing carbon atoms. Hence, the structure of ‘A’ can be represented as: XC = CX There are 8 C–H $$\sigma$$ bonds which state that there are 8 hydrogen atoms in ‘A’. Also, there are 3 C–C bonds which state that there are 4 carbon atoms present in the same.
Combining the information given, the structure of ‘A’ can be represented as:

‘A’ has 3 C-C bonds, 8 C-H $$\sigma$$ bonds along with a C-C$$\pi$$ bond which states that the IUPAC name of the same is But-2-ene. Now, Ozonolysis of ‘A’ takes place as;

Here, we can say that the final product is being proved as ethanal with molar mass 44u.

Answered by Abhisek | 1 year ago

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