Draw the cis and trans structures of hex-2-ene. Which isomer will have higher b.p. and why?

Asked by Pragya Singh | 1 year ago |  58

##### Solution :-

Hex-2-ene is represented as

$$CH_3- CH =CH - CH_2 -CH_2 -CH_3 .$$

Geometrical isomers of hex-2-ene are:

The dipole moment of cis-compound is a sum of the dipole moments of $$C -CH_3\; and\;C - CH_2 CH_2 CH_3$$ bonds acting in the same direction. The dipole
moment of a trans-compound is the resultant of the dipole moments of the same bonds acting in opposite directions. Thus, cis-isomer is more polar than trans-isomer. The higher the polarity, the greater is the intermolecular dipole-dipole interaction and the higher will be the boiling point. Therefore, cis-isomer will have a higher boiling point than trans-isomer.

Answered by Abhisek | 1 year ago

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