Explain why the following systems are not aromatic?

(i)

(ii)

(iii)

Asked by Pragya Singh | 1 year ago |  50

##### Solution :-

(i) In the given compound, one carbon atom is sp3 hybridized which signifies that it is tetrahedral (not planar). As for the compound to be aromatic, it should be planar. Thus, the given compound is not aromatic in nature.

(ii) In the given compound, one carbon atom is sp3 hybridized which signifies that it is tetrahedral (not planar). As for the compound to be aromatic, it should be planar.
Also, for the given compound, the number of $$\pi-$$electrons is 4 so, by Huckel’s rule;

4n + 2 = 4

$$n=\dfrac{1}{2}$$

For a compound to be aromatic, the value of n must be an integer i.e. 0, 1, 2… etc. which is not satisfied for the given compound. Therefore, it is not aromatic in nature.

(iii) For the given compound, the number of $$\pi-$$ electrons is 8 so, by Huckel’s rule;

4n + 2 = 8

$$n=\dfrac{2}{3}$$

Answered by Abhisek | 1 year ago

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