Out of benzene, m–dinitrobenzene and toluene, state the increasing order of nitration. Justify your answer?

Asked by Abhisek | 1 year ago |  171

#### 1 Answer

##### Solution :-

The ease of nitration depends on the presence of electron density on the compound to form nitrates. Nitration reactions are examples of electrophilic substitution reactions where an electron-rich species is attacked by a nitronium ion $$(NO_2^{+})$$. Now as we know, $$(CH_3^{–})$$ group is electron donating and $$(NO_2^{–})$$ is electron
withdrawing. Therefore, toluene will have the maximum electron density among the 3 compounds followed by benzene. On the other hand, m– Dinitrobenzene will have the least electron density. Thus, it will undergo nitration with difficulty. Hence, the increasing order of nitration is as;

Answered by Abhisek | 1 year ago

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