Indicate the σ and π bonds in the molecules: CH3NO2

Asked by Pragya Singh | 1 year ago |  166

##### Solution :-

There are three C–H sigma bonds, one C–N sigma bond, one N–O sigma bond, and one N=O pi bond in the given compound.

Answered by Pragya Singh | 1 year ago

### Related Questions

#### Which of the following carbocation is most stable?

Which of the following carbocation is most stable?

(a) $$(CH_3)_3 C.C^{+}H_2$$

(b) $$(CH_3)_3\; C^{+}$$

(c) $$CH_3 CH_2C^{+}H_2$$

(d) $$CH_3 C^{+}HCH_2CH_3$$

#### The reaction: CH_3 CH_2 I+KOH_{(aq)}CH_3 CH_2 OH +KI is classified as : (a) electrophilic substitution

The reaction:

$$CH_3 CH_2 I+KOH_{(aq)} \rightarrow CH_3 CH_2 OH +KI$$ is classified as :

(a) electrophilic substitution

(b) nucleophilic substitution

(c) elimination

#### The best and latest technique for isolation, purification and separation of organic compounds is

The best and latest technique for isolation, purification and separation of organic compounds is:

(a) Crystallisation

(b) Distillation

(c) Sublimation

(d) Chromatography

#### In the Lassaigne’s test for nitrogen in an organic compound, the Prussian blue colour is obtained

In the Lassaigne’s test for nitrogen in an organic compound, the Prussian blue colour is obtained due to the formation of:

(a) $$Na_4[Fe(CN)_6]$$

(b) $$Fe_4[Fe(CN)_6]_3$$

(c) $$Fe_2[Fe(CN)_6]$$

(d) $$Fe_3[Fe(CN)_6]_4$$

#### In the organic compound CH2=CH–CH2–CH2–C≡CH, the pair of hydridised orbitals

In the organic compound $$CH_2=CH–CH_2–CH_2–C≡CH$$, the pair of hydridised orbitals involved in the formation of: $$C_2 – C_3$$ bond is:

(a) sp – sp2

(b) sp – sp3

(c) sp2– sp3

(d) sp3– sp3