What is the state of hybridisation of carbon in

(a) CO32–

(b) diamond

(c) graphite?

Asked by Pragya Singh | 11 months ago |  42

##### Solution :-

(a) As the carbon atom in carbonate ion ($$CO_3^{2-}$$) is bonded to three oxygen atoms so, the hybridization is sp2 .

(b) The hybridization of carbon atom in diamond is sp3 because each carbon atom is attached with four different carbon atoms.

(c) The hybridization of carbon atom in graphite is sp2 because each carbon atom is attached with three different carbon atoms.

Answered by Abhisek | 11 months ago

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