Explain the following reactions

(a) Silicon is heated with methyl chloride at high temperature in the presence of copper;

(b) Silicon dioxide is treated with hydrogen fluoride;

(c) CO is heated with ZnO;

(d) Hydrated alumina is treated with aqueous NaOH solution.

Asked by Pragya Singh | 1 year ago |  50

1 Answer

Solution :-

(a) At 537 K, silicon combines with methyl chloride in the presence of copper (catalyst) to create methyl substituted chlorosilanes (MeSiCl3 , Me2 SiCl2 ,
Me3SiCl and Me4Si ),a family of organosilicon polymers. The reaction is given below:

(b) If you heat silicon dioxide with hydrogen fluoride, you get silicon tetrafluoride(SiF4). Even at high temperatures the Si–O bond is usually a strong bond that is resistant to assault by halogens and most acids. HF, on the other hand, is a serious threat to its survival.

Hydrofluorosilicic acid may be produced by reacting SiF4 with HF. The reaction is given below:

(c) CO reduces ZnO to Zn when it interacts with ZnO. CO acts as a reducing agent. The reaction is given below:

(d) Due to the formation of sodium meta-aluminate, hydrated alumina and sodium hydroxide dissolve one another. The reaction is given below:

Answered by Abhisek | 1 year ago

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