A certain salt X, gives the following results.

(i) Its aqueous solution is alkaline to litmus.

(ii) It swells up to a glassy material Y on strong heating.

(iii) When conc. $$H_2SO_4$$is added to a hot solution of X, white crystal of an acid Z separates out.

Write equations for all the above reactions and identify X, Y and Z.

Asked by Abhisek | 1 year ago |  53

##### Solution :-

Using a litmus test, the salt provided is alkali. Because of this, the compound X is salt of a strong acid and a weak base. A similar phenomenon occurs when the material X is heated to extreme temperatures. As a result, X is borax. The sodium metaborate is formed when borax is heated and the water evaporates, forming sodium metaborate. Continued heating solidifies it into a glassy substance Y. The combination of sodium metaborate and boric anhydride, is Y.

When concentrated acid is added to borax, white crystals of orthoboric acid (Z) are formed.

Answered by Pragya Singh | 1 year ago

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