Arrange the following  NaH, MgH2 and H2O in order of increasing reducing property.

Asked by Abhisek | 11 months ago |  44

1 Answer

Solution :-

Ionic hydrides are strong reducing agents.  NaH can easily donate its electrons. Hence, it is most reducing in nature. Both, MgH2 and H2O are covalent hydrides. H2O is less reducing than MgH2 since the bond dissociation energy of H2 O is higher than MgH2. Hence, the increasing order of the reducing property is H2O < MgH2 < NaH.

Answered by Pragya Singh | 11 months ago

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