The process of treating permanent hardness of water using synthetic resins generally based on exchange of anions and cations present in water by OH– and H+ ions, respectively.
Two types of synthetic resins are
Cation exchange resins are large organic molecules that contain the –SO3H group. Firstly the resin get changed into RNa by treating it with NaCl. This resin exchanges Na+ ions with Ca2+ ions and Mg2+ ions, thereby making the water soft.
\( 2RNa+M^{2+}_{(aq)}\rightarrow R_{2}M_{(s)}+2Na^{+}_{(aq)} \)
There are cation exchange resins in H+ form. The resins exchange H+ ions for Na+, Ca2+, and Mg2+ ions.
\( 2RH+M^{2+}_{(aq)}\rightleftharpoons MR_{2(s)}+2H^{+}_{(aq)} \)
Anion exchange resins exchange OH– ions for anions like Cl– , \( HCO^{-}_{3}\)and \( SO_{4}^{2-}\) present in water.
\( RNH_{2(s)}+H_{2}O_{(l)} \rightleftharpoons \)
\( RNH^{+}_{3}.OH^{-}_{(s)} RNH^{+}_{3}.X^{-}_{(s)}+OH^{-}_{aq)}\)
During the whole process, first the water passes through the cation exchange process. The water which is obtained after this process is free from mineral cations and naturally acidic. This acidic water is then passed through the anion exchange process where OH– ions neutralize the H+ ions and de-ionize the water obtained.
Answered by Pragya Singh | 1 year agoWhat do you understand by the terms :
(i) Hydrogen economy
(ii) Hydrogenation
(iii) ‘syngas’
(iv) Water-gas shift reaction
(v) Fuel cell?
Do you expect different products in solution when aluminium (III) chloride and potassium chloride treated separately with
(i) alkaline water
(ii) acidified water, and
(iii) normal water. Write equations wherever necessary.
What do you expect the nature of hydrides is, if formed by elements of atomic numbers 15, 19, 23 and 44 with dihydrogen? Compare their behaviour with water.
How can saline hydrides remove traces of water from organic compounds?