An object 5 cm in length is held 25 cm away from a converging lens of focal length 10 cm. Draw the ray diagram and find the position, size, and nature of the image formed.

Asked by Vishal kumar | 2 years ago |  198

##### Solution :-

Height of the Object, h0 = 5 cm

Distance of the object from converging lens, u = -25 cm

Focal length of converging lens, f = 10 cm

Using lens formula,

$$\frac{1}{v}-\frac{1}{u}=\frac{1}{f}$$

$$\frac{1}{v}=\frac{1}{f}+\frac{1}{u}=\frac{1}{10}-\frac{1}{25}=\frac{15}{250}$$

$$v = \frac{250}{15}= 16.06 cm$$

Also, for a converging lens, $$\frac{h_i}{h_o}=\frac{v}{u}$$

$$h_i=\frac{v}{u}\times\,h_o=\frac{50\times5}{3\times(-25)}=\frac{10}{-3}= -3.3 cm$$

Thus, the image is inverted and formed at a distance of 16.7 cm behind the lens and measures 3.3 cm. The ray diagram is shown below.

Answered by Shivani Kumari | 2 years ago

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