A concave lens of focal length 15 cm forms an image 10 cm from the lens. How far is the object placed from the lens? Draw the ray diagram.

Asked by Vishal kumar | 1 year ago |  161

Solution :-

Focal length of concave lens (OF1), f = - 15 cm

Image distance, v= - 10 cm

According to the lens formula,

$$\frac{1}{v}-\frac{1}{u}=\frac{1}{f}$$

$$\frac{1}{u}=\frac{1}{v}-\frac{1}{f}=-\frac{1}{10}-\frac{1}{15}=\frac{1}{10}+\frac{1}{15}$$

The negative value of u indicates that the object is placed 30 cm in front of the lens. This is shown in the following ray diagram.

Answered by Shivani Kumari | 1 year ago

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