1 Answer
Solution :-
Focal length of concave lens (OF1), f = - 15 cm
Image distance, v= - 10 cm
According to the lens formula,
\( \frac{1}{v}-\frac{1}{u}=\frac{1}{f}\)
\( \frac{1}{u}=\frac{1}{v}-\frac{1}{f}=-\frac{1}{10}-\frac{1}{15}=\frac{1}{10}+\frac{1}{15}\)
The negative value of u indicates that the object is placed 30 cm in front of the lens. This is shown in the following ray diagram.
Related Questions
A doctor has prescribed a corrective lens of power +1.5 D. Find the focal length of the lens. Is the prescribed lens diverging or converging?
Find the focal length of a lens of power -2.0 D. What type of lens is this?
An object of size 7.0 cm is placed at 27 cm in front of a concave mirror of focal length 18 cm. At what distance from the mirror should a screen be placed so that a sharply focused image can be obtained? Find the size and the nature of the image.
An object 5 cm is placed at a distance of 20 cm in front of a convex mirror of radius of curvature 30 cm. Find the position, nature, and size of the image.
The magnification produced by a plane mirror is +1. What does this mean?