While sulphur dioxide and hydrogen peroxide can act as oxidising as well as reducing agents in their reactions, ozone and nitric acid act only as oxidants. Why?

Asked by Pragya Singh | 1 year ago |  63

1 Answer

Solution :-

In sulphur dioxide\( (SO_{ 2 })\) the oxidation no. of S is +4 and the range of oxidation no. of sulphur is from +6 to -2.

Hence, \( SO_{ 2 }\)​ can act as a reducing and oxidising agent.

\( H_{ 2 }O_{ 2 }\)

In hydrogen peroxide \( H_{ 2 }O_{ 2 }\) the oxidation no. of O is -1 and the range of the oxidation no. of oxygen is from 0 to -2. Oxygen can sometimes attain the oxidation no. +1 and +2.

Therefore, \( H_{ 2 }O_{ 2 }\) can act as a reducing and oxidising agent.

 

In ozone \( (O_{ 3 })\) the oxidation no. of O is 0 and the range of the oxidation no. of oxygen is from 0 to –2. Hence, the oxidation no. of oxygen only decreases in this case.

Therefore,\( O_{ 3 }\)​ acts only as an oxidant.

 

In nitric acid \( HNO_{ 3 }\)the oxidation no. of nitrogen is +5 and the range of the oxidation no. that nitrogen can have is from +5 to -3. Hence, the oxidation no. of nitrogen can only decrease in this case.

Therefore, \( HNO_{ 3 }\)​ acts only as an oxidant.

Answered by Abhisek | 1 year ago

Related Questions

Fluorine reacts with ice and results in the change: 

\( H_{ 2 }O_{ (s) } \; + \; F_{ 2 \; (g) } \; \rightarrow \; HF_{ (g) } \; + \; HOF_{ (g) } \)

Justify that this reaction is a redox reaction

Class 11 Chemistry Redox Reactions View Answer

Depict the galvanic cell in which the reaction is:

\( Zn_{\left ( s \right )} \;+ \;2 \;Ag_{\left ( aq \right )}^{+} \;\rightarrow \;Zn^{2+}_{\left ( aq \right )} \;+ \;2 \;Ag_{\left ( s \right )} \)

Further show:

(i) which of the electrode is negatively charged?

(ii) the carriers of the current in the cell.

(iii) individual reaction at each electrode.

Class 11 Chemistry Redox Reactions View Answer

Given the standard electrode potentials,

\( \dfrac{ K^{+}}{K}\)= –2.93V

\( \dfrac{ Ag^{+}}{Ag}\) = 0.80V

\( \dfrac{Hg^{2+}}{Hg}\) = 0.79V

\(\dfrac{ Mg^{2+}}{Mg}\) = –2.37V

\(\dfrac{Cr^{3+}}{Cr}\) = –0.74V

Arrange these metals in their increasing order of reducing power.

Class 11 Chemistry Redox Reactions View Answer

Arrange the given metals in the order in which they displace each other from the solution of their salts.

Al, Fe, Cu, Zn, Mg

Class 11 Chemistry Redox Reactions View Answer

Predict the products of electrolysis in each of the following:

(i) An aqueous solution of \( AgNO_{3}\) with silver electrodes

(ii) An aqueous solution \( AgNO_{3}\)​ with platinum electrodes

(iii) A dilute solution of \( H_{2}SO_{4}\)​ with platinum electrodes

(iv) An aqueous solution of \( CuCl_{2}\)with platinum electrodes.

Class 11 Chemistry Redox Reactions View Answer