Focal length of convex mirror (f) = +15 cm
Object distance (u) = - 10 cm
According to the mirror formula,
\( \frac{1}{v}=\frac{1}{f}-\frac{1}{u}\)
\( \frac{1}{v}=\frac{1}{15}-\frac{1}{-10} =\frac{2+3}{30}\)
\( v = \frac{5}{30}= 6 cm\)
\( Magnification =\frac{-v}{u}=\frac{-6}{-10}=0.6\)
The image is located at a distance of 6 cm from the mirror on the other side of the mirror. The positive and a value less than 1 of magnification indicates that the image formed is virtual and erect and diminished.
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