Focal length of convex mirror (f) = +15 cm

Object distance (u) = - 10 cm

According to the mirror formula,

\( \frac{1}{v}=\frac{1}{f}-\frac{1}{u}\)

\( \frac{1}{v}=\frac{1}{15}-\frac{1}{-10} =\frac{2+3}{30}\)

\( v = \frac{5}{30}= 6 cm\)

\( Magnification =\frac{-v}{u}=\frac{-6}{-10}=0.6\)

The image is located at a distance of 6 cm from the mirror on the other side of the mirror. The positive and a value less than 1 of magnification indicates that the image formed is virtual and erect and diminished.

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