Write the expression for the equilibrium constant, Kc for each of the following reactions:

(i) $$2NOCl(g)\leftrightarrow 2NO(g)+Cl_{2}(g)$$

(ii) $$2Cu(NO_{3})_{2}(s)\leftrightarrow 2CuO(s)$$

$$+4NO_{2}(g)+O_{2}(g)$$

(iii) $$CH_{3}COOC_{2}H_{5}(aq)+H_{2}O(1)$$

$$\leftrightarrow CH_{3}COOH(aq)+C_{2}H_{5}OH(aq)$$

(iv) $$Fe^{3+}(aq)+3OH^{-}(aq)\leftrightarrow Fe(OH)_{3}(s)$$

(v) $$I_{2}(s)+5F_{2}\leftrightarrow 2IF_{5}$$

Asked by Pragya Singh | 1 year ago |  90

##### Solution :-

(i) $$K_{C}=\dfrac{[NO_{g}]^{2}[Cl_{2_{(g)}}]}{[NOCl_{(g)}]^{2}}$$

(ii) $$K_{C}=\dfrac{[CuO_{(s)}]^{2}[NO_{2_{(g)}}]^{4}[O_{2_{(g)}}]}{[Cu(NO_{3})_{2(g)}]^{2}}\\ \\$$

$$=[NO_{2(g)}]^{4}[O_{2(g)}]$$

(iii) $$K_{C}=\dfrac{[CH_{3}COOH_{(aq)}][C_{2}H_{5}OH_{(aq)}]}{[CH_{3}COOC_{2}H_{5(aq)}][H_{2}O_{(l)}]}\\ \\$$

$$=\dfrac{[CH_{3}COOH_{(aq)}][C_{2}H_{5}OH_{(aq)}]}{[CH_{3}COOC_{2}H_{5(aq)}]}$$

(iv) $$K_{C}=\dfrac{[Fe(OH)_{3(s)}]}{[Fe^{3+}_{(aq)}][OH^{-}_{(aq)}]^{3}}\\ \\$$

$$=\dfrac{1}{[Fe^{3+}_{(aq)}][OH^{-}_{(aq)}]^{3}}$$

(v) $$K_{C}=\dfrac{[IF_{5}]^{2}}{[I_{2(s)}][F_{2}]^{5}}\\ \\$$

$$=\dfrac{[IF_{5}]^{2}}{[F_{2}]^{5}}$$

Answered by Pragya Singh | 1 year ago

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