The relation between K_{p} and K_{c} is given as:

\( K_{p}=K_{c}(RT)^{\Delta n}\)

**(i)** Given,

R = 0.0831 bar mol^{–1}K^{–1}

\( \Delta n = 3-2 =1\)

T = 500 K

K_{p}=\( 1.8\times 10^{-2}\)

Now,

K_{p} = K_{c} (RT) ^{∆n}

\( \Rightarrow 1.8\times 10^{-2}=K_{c}(0.0831\times 500)^{1}\\ \\ \)

\( \Rightarrow K_{c}=\dfrac{1.8\times 10^{-2}}{0.0831\times 500}\\ \\\)

\( =4.33\times 10^{-4}(approximately)\)

**(ii)** Here,

∆n =2 – 1 = 1

R = 0.0831 bar mol^{–1}K^{–1}

T = 1073 K

K_{p}= 167

Now,

K_{p} = K_{c }(RT) ^{∆n}

\( \Rightarrow 167=K_{c}{(0.0831\times 1073)^{\Delta n}}\\ \\ \Rightarrow K_{c}=\dfrac{167}{0.0831\times 1073}\\ \\ =1.87(approximately)\)

Answered by Pragya Singh | 1 year agoThe concentration of sulphide ion in 0.1M HCl solution saturated with hydrogen sulphide is 1.0 × 10^{–19} M. If 10 mL of this is added to 5 mL of 0.04M solution of the following: FeSO_{4}, MnCl_{2}, ZnCl_{2} and CdCl_{2} . in which of these solutions precipitation will take place?

What is the minimum volume of water required to dissolve 1g of calcium sulphate at 298 K? (For calcium sulphate, K_{sp} is 9.1 × 10^{–6}).

What is the maximum concentration of equimolar solutions of ferrous sulphate and sodium sulphide so that when mixed in equal volumes, there is no precipitation of iron sulphide? (For iron sulphide, Ksp = 6.3 × 10^{–18}).

The ionization constant of benzoic acid is 6.46 × 10^{–5} and Ksp for silver benzoate is 2.5 × 10^{–13}. How many times is silver benzoate more soluble in a buffer of pH 3.19 compared to its solubility in pure water?

Equal volumes of 0.002 M solutions of sodium iodate and cupric chlorate are mixed together. Will it lead to precipitation of copper iodate? (For cupric iodate K_{sp} = 7.4 × 10^{–8} ).