Object distance (u) = - 27 cm

Object height (h) = 7 cm

Focal length (f) = - 18 cm

According to the mirror formula,

\( \frac{1}{v}-\frac{1}{u}=\frac{1}{f}\)

\( \frac{1}{v}=\frac{1}{f}+\frac{1}{u}\)

\( =-\frac{1}{18}+\frac{1}{27}=-\frac{1}{54}\)

v = -54 cm

The screen should be placed at a distance of 54 cm in front of the given mirror

\( Magnification,m=-\frac{Image\,Distance}{Object\,Distance}=\frac{-54}{27}=-2\)

The negative value of magnification indicates that the image formed is real

\( Magnification,m=\frac{Height\,of\,the\,image}{Height\,of\,the\,object}=\frac{h^1}{h}\)

\(h^1=m\times h=7\times -2=-14cm\)

The negative value of image height indicates that the image formed is inverted

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