At 450 K, Kp$$2.0 \times 10^{10}$$bar for the given reaction at equilibrium.

2SO2(g)+O2(g) ⇌ 2SO3(g) What is Kc at this temperature?

Asked by Abhisek | 11 months ago |  101

#### 1 Answer

##### Solution :-

For the given reaction,

∆n = 2 – 3 = – 1

T = 450 K

R = 0.0831 bar L bar K–1 mol–1

Kp=$$2.0 \times 10^{10}bar^{-1}$$

We know that,

Answered by Pragya Singh | 11 months ago

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