Kp = 0.04 atm at 899 K for the equilibrium shown below. What is the equilibrium concentration of C2H6 when it is placed in a flask at 4.0 atm pressure and allowed to come to equilibrium?

C2H6(g) ⇌ C2H4(g) +H2(g)

Asked by Pragya Singh | 1 year ago |  95

##### Solution :-

Let p be the pressure exerted by ethene and hydrogen gas (each) at equilibrium. Now, according to the reaction,

C2H6(g)   ⇌    C2H4(g)    +     H2(g)

Initial conc.      4.0 M      0           0

At equilibrium  (4.0-p)     p          p

We can write,

$$\dfrac{p_{c_{2}H_{4}}\times p_{H_{2}}}{p_{c_{2}H_{6}}}$$

$$=K_{P}\\ \\ \Rightarrow \dfrac{p\times p}{40-p}=0.04\\ \\$$

$$\Rightarrow p^{2}=0.16-0.04p\\ \\$$

$$\Rightarrow p^{2}+0.04p-0.16$$

Now,

$$p=\dfrac{-0.04\pm \sqrt{(0.04)^{2}-4\times 1\times (-0.16)}}{2\times 1}\\ \\ =\dfrac{-0.04\pm 0.80}{2}\\ \\ =\dfrac{0.76}{2}\: \: \: \: \: \: \: \: \: (Taking \:positive\: value)\\ \\ =0.38p$$

Hence, at equilibrium, [C2H6

= 4 – p = 4 – 0.38

= 3.62 atm

Answered by Abhisek | 1 year ago

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