Ethyl acetate is formed by the reaction between ethanol and acetic acid and the equilibrium is represented

(i) Reaction quotient,

\( Q_{c}=\dfrac{[CH_{3}COOC_{2}H_{5}][H_{2}O]}{[CH_{3}COOH][C_{2}H_{5}OH]}\)

(ii) Let the volume of the reaction mixture be V. Also, here we will consider that water is a solvent and is present in excess.

The given reaction is:

CH₃COOH_(l) +  C₂H₅OH_(l)  ⇌ CH₃COOC₂H_5(l) + H₂O_(l)

Initial conc.         1/V M             0.18/V M      0        0

At equilibrium (1-0.171)/V ,    (0.18 – 0.171)/V,    0.171/V M,  0.171/V M

= 0.829/V M    = 0.009/V M

Therefore, equilibrium constant for the given reaction is:

\( K_{c}=\dfrac{[CH_{3}COOC_{2}H_{5}][H_{2}O]}{[CH_{3}COOH][C_{2}H_{5}OH]}\\ \\\)

\( =\dfrac{\dfrac{0.171}{V}\times \dfrac{0.171}{V}}{\dfrac{0.829}{V}\times \dfrac{0.009}{V}}=3.919\\ \\ \)

\( =3.92(approximately)\)

(iii) Let the volume of the reaction mixture be V.

CH₃COOH(l)+C₂H₅OH(l)   ⇌  CH₃COOC₂H₅(l)+H₂O(l)

Initial conc.           1.0/V M           0.5/V M                   0                      0

At equilibrium  (10-0.214)/V,      (0.5-0.214)/V,         0.214/V M,       0.214/V M

= 0.786/V M     = 0.286/V M

Therefore, the reaction quotient is,

\( K_{c}=\dfrac{[CH_{3}COOC_{2}H_{5}][H_{2}O]}{[CH_{3}COOH][C_{2}H_{5}OH]}\\ \\ \)

\( =\dfrac{\dfrac{0.214}{V}\times \dfrac{0.214}{V}}{\dfrac{0.786}{V}\times \dfrac{0.286}{V}}=0.2037\\ \\ \)

\( =0.204(approximately)\)

Since Q_cc , equilibrium has not been reached.