The pH of 0.1M solution of cyanic acid (HCNO) is 2.34. Calculate the ionization constant of the acid and its degree of ionization in the solution.

Asked by Pragya Singh | 1 year ago |  65

Solution :-

c = 0.1 M

pH = 2.34

-log [H+] = pH

-log [H+] = 2.34

[H+]=4.5× 10-3

Also,

[H+]=cα

4.5 × 10-3 = 0.1× α

α = $$\dfrac{ 0.1}{(4.5 × 10^{-3})}$$

α = 0.045

Ka = cα2

Ka = 0.1 × (0.045)2

Ka = 0.0002025

Ka = 2.025 x 10-4

Answered by Abhisek | 1 year ago

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