Ionic product of water at 310 K is 2.7 × 10–14. What is the pH of neutral water at this temperature?

Asked by Pragya Singh | 1 year ago |  135

#### 1 Answer

##### Solution :-

Ionic Product,$$K_{w} = [H^{+}][OH^{-}]$$

Assuming,$$H^{+}= y$$

As,$$[H^{+}] = [OH^{-}]$$,

Thus, the pH of neutral water at 310K temperature is 6.78.

Answered by Abhisek | 1 year ago

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