An electric oven of 2 kW power rating is operated in a domestic electric circuit (220 V) that has a current rating of 5 A. What result do you expect? Explain.

Asked by Vishal kumar | 1 year ago |  157

Solution :-

The current drawn by the electric oven can be calculated using the formula

$$P=V\times I$$

$$I=\frac{P}{V}$$

Substituting the values, we get

$$I=\frac{200\, W}{220\,V}=9.09\,A$$

The current drawn by the electric oven is 9.09 A, which exceeds the safe limit of the circuit. This causes the fuse to melt and break the circuit.

Answered by Shivani Kumari | 1 year ago

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