It can be written as

A = {x: x is a natural number} = {1, 2, 3, 4, 5 …}

B ={x: x is an even natural number} = {2, 4, 6, 8 …}

C = {x: x is an odd natural number} = {1, 3, 5, 7, 9 …}

D = {x: x is a prime number} = {2, 3, 5, 7 …}

**(i) **A ∩B = {x: x is a even natural number} = B

**(ii)** A ∩ C = {x: x is an odd natural number} = C

**(iii) **A ∩ D = {x: x is a prime number} = D

**(iv)** B ∩ C = Φ

**(v)** B ∩ D = {2}

**(vi)** C ∩ D = {x: x is odd prime number}

Find the symmetric difference A Δ B, when A = {1, 2, 3} and B = {3, 4, 5}.