(i) It is given that
U = {1, 2, 3, 4, 5, 6, 7, 8, 9}
A = {1, 2, 3, 4}
B = {2, 4, 6, 8}
C = {3, 4, 5, 6}
To find, A'
The complement of set A is the set of all elements of U which are not the elements of A.
A' = U−A
{1, 2, 3, 4, 5, 6, 7, 8, 9} - {1, 2, 3, 4}
= {5, 6, 7, 8, 9}
A’ = {5, 6, 7, 8, 9}
(ii) To find, B'
The complement of set A is the set of all elements of U which are not the elements of A.
B' = U−B
{1, 2, 3, 4, 5, 6, 7, 8, 9} - {2, 4, 6, 8}
= {1, 3, 5, 7, 9}
B’ = {1, 3, 5, 7, 9}
(iii) To find, (A U C)'
The complement of set A is the set of all elements of U which are not the elements of A.
A U C = {1, 2, 3, 4, 5, 6}
(A U C)' = U − (A U C)
{1, 2, 3, 4, 5, 6, 7, 8, 9} - {1, 2, 3, 4, 5, 6}
= {7, 8, 9}
(A U C)’ = {7, 8, 9}
(iv) To find, (A U B)’
{1, 2, 3, 4, 5, 6, 7, 8, 9} - {1, 2, 3, 4, 5, 6, 7, 8}
The complement of set A is the set of all elements of U which are not the elements of A.
= {5, 7, 9}
(A U B)’ = {5, 7, 9}
(v) To find, (A')'
The complement of set A is the set of all elements of U which are not the elements of A.
(A')' = A
= {1, 2, 3, 4}
(A’)’ = {1, 2, 3, 4}
(vi) To find, (B− C)'
The complement of set A is the set of all elements of U which are not the elements of A.
B − C = {2,8}
(B− C)' = U − (B− C)
{1, 2, 3; 4, 5, 6, 7, 8, 9} - {2,8}
= {1, 3, 4, 5, 6, 7, 9}
So we get
(B – C)’ = {1, 3, 4, 5, 6, 7, 9}
Answered by Pragya Singh | 1 year agoFind the symmetric difference A Δ B, when A = {1, 2, 3} and B = {3, 4, 5}.