**(i)** Given that,

The set of natural number is the universal set

To find the complement of the set of perfect squares.

The complement of set A is the set of all elements of U which are not the elements of A.

{x: x is a perfect square}´ = {x: x ∈ N and x is not a perfect square}

**(ii) **Given that,

The set of natural number is the universal set

To find the complement of the set of perfect cube

The complement of set A is the set of all elements of U which are not the elements of A.

{x: x is a perfect cube}´ = {x: x ∈ N and x is not a perfect cube}

**(iii) **Given that,

The set of natural number is the universal set

To find the complement of {x: x + 5 = 8}

x +5 =8

x = 3

The complement of set A is the set of all elements of U which are not the elements of A.

{x: x + 5 = 8}´ = {x: x ∈ N and x ≠ 3}

**(iv)** Given that,

The set of natural number is the universal set

To find the complement of the {x: 2x + 5 = 9}

The complement of set A is the set of all elements of U which are not the elements of A.

2x +5 = 9

2x = 4

x = 2

{x: 2x + 5 = 9}´ = {x: x ∈ N and x ≠ 2}

**(v)** Given that,

The set of natural number is the universal set

To find the complement of {x: x ≥ 7}

The complement of set A is the set of all elements of U which are not the elements of A.

{x: x ≥ 7}´ = {x: x ∈ N and x < 7}

**(vi) **Given that,

The set of natural number is the universal set

To find the complement of the** **{x: x ∈ N and 2x + 1 > 10}

The complement of set A is the set of all elements of U which are not the elements of A.

2x +1>10

2x > 9

\( x>\dfrac{9}{2}\)

{x: x ∈ N and 2x + 1 > 10}´ = {x: x ∈ N and x ≤ \( \dfrac{9}{2}\)}

Answered by Sudhanshu | 1 year agoFind the symmetric difference A Δ B, when A = {1, 2, 3} and B = {3, 4, 5}.