(i) Given that,
The set of natural number is the universal set
To find the complement of the set of perfect squares.
The complement of set A is the set of all elements of U which are not the elements of A.
{x: x is a perfect square}´ = {x: x ∈ N and x is not a perfect square}
(ii) Given that,
The set of natural number is the universal set
To find the complement of the set of perfect cube
The complement of set A is the set of all elements of U which are not the elements of A.
{x: x is a perfect cube}´ = {x: x ∈ N and x is not a perfect cube}
(iii) Given that,
The set of natural number is the universal set
To find the complement of {x: x + 5 = 8}
x +5 =8
x = 3
The complement of set A is the set of all elements of U which are not the elements of A.
{x: x + 5 = 8}´ = {x: x ∈ N and x ≠ 3}
(iv) Given that,
The set of natural number is the universal set
To find the complement of the {x: 2x + 5 = 9}
The complement of set A is the set of all elements of U which are not the elements of A.
2x +5 = 9
2x = 4
x = 2
{x: 2x + 5 = 9}´ = {x: x ∈ N and x ≠ 2}
(v) Given that,
The set of natural number is the universal set
To find the complement of {x: x ≥ 7}
The complement of set A is the set of all elements of U which are not the elements of A.
{x: x ≥ 7}´ = {x: x ∈ N and x < 7}
(vi) Given that,
The set of natural number is the universal set
To find the complement of the {x: x ∈ N and 2x + 1 > 10}
The complement of set A is the set of all elements of U which are not the elements of A.
2x +1>10
2x > 9
\( x>\dfrac{9}{2}\)
{x: x ∈ N and 2x + 1 > 10}´ = {x: x ∈ N and x ≤ \( \dfrac{9}{2}\)}
Answered by Sudhanshu | 1 year agoFind the symmetric difference A Δ B, when A = {1, 2, 3} and B = {3, 4, 5}.