Let U be the set of all triangles in a plane. If A is the set of all triangles with at least one angle different from 60°, what is A’?

Asked by Pragya Singh | 11 months ago |  67

1 Answer

Solution :-

Given that,

U is the set of all triangles in the plane

A = Set of triangles different form 60°

To find A'

The complement of set A is the set of all elements of U which are not the elements

of A.

A' = U−A

=Set of all equilateral triangles

A' is the set of all equilateral triangles

Answered by Pragya Singh | 11 months ago

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