We are provided with the fact, R = {(x, x + 5): x ∈ {0, 1, 2, 3, 4, 5}}
Using the condition given,
We can clearly write that, R = {(0, 5), (1, 6), (2, 7), (3, 8), (4, 9), (5, 10)}
And this is our needed relation.Now, it can be clearly observed, that the domain of
R is, {(x : x ∈ (0,1,2,3,4,5)} . And similarly, the range of R is, {(y : y ∈ (5,6,7,8,9,10)} .
Answered by Abhisek | 1 year agoLet R = {(a, b) : a, b, ϵ N and a < b}.Show that R is a binary relation on N, which is neither reflexive nor symmetric. Show that R is transitive.
Let A = {3, 4, 5, 6} and R = {(a, b) : a, b ϵ A and a
(i) Write R in roster form.
(ii) Find: dom (R) and range (R)
(iii) Write R–1 in roster form
Let A = (1, 2, 3} and B = {4} How many relations can be defined from A to B.
Let R = {(x, x2) : x is a prime number less than 10}.
(i) Write R in roster form.
(ii) Find dom (R) and range (R).
If A = {5} and B = {5, 6}, write down all possible subsets of A × B.