Since either coin can turn up Head (H) or Tail (T), are the possible outcomes.
Let us assume that 1, 2, 3, 4, 5 and 6 are the possible outcomes when the die is thrown.
The following problem can be divided in two cases
(i) The number on the die is even.
The sample space SE={(2,H),(4,H),(6,H),(2,T),(4,T),(6,T)}
(ii) The number on the die is odd and the coin is tossed twice.
The sample space
So = {(1,H,H), (3,H,H), (5,H,H), (1,H,T), (3,H,T), (5,H,T), (1,T,H), (3,T,H), (5,T,H), (1,T,T), (3,T,T), (5,T,T)}
Hence, the overall sample space for the problem= SE + So
S = {(2,H), (4,H), (6,H), (2,T), (4,T), (6,T), (1,H,H), (3,H,H), (5,H,H), (1,H,T), (3,H,T), (5,H,T), (1,T,H), (3,T,H), (5,T,H), (1,T,T), (3,T,T), (5,T,T)}
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