Since either coin can turn up Head (H) or Tail (T), are the possible outcomes.

Let us assume R_{1}, R_{2} denote the event the red balls are drawn and B_{1}, B_{2}, B_{3} denote the events black ball are drawn.

Let us assume that 1, 2, 3, 4, 5 and 6 are the possible outcomes when the die is thrown.

**(i)** Coin shows Tail.

So, the sample space S_{T }= {(TR_{1}), (TR_{2}), (TB_{1}), (TB_{2}), (TB_{3})}

**(ii)** Coin shows head.

So, the sample space S_{H }= {(H,1), (H,2), (H,3), (H,4), (H,5), (H,6)}

Hence, the overall sample space for the problem= S_{T }+ S_{H}

S = {( T,R_{1}), (T,R_{2}), (T,B_{1}), (T,B_{2}), (T,B_{3}), (H,1), (H,2), (H,3), (H,4), (H,5), (H,6)}

One number is chosen from numbers 1 to 100. Find the probability that it is divisible by 4 or 6?

The probability that a student will pass the final examination in both English and Hindi is 0.5 and the probability of passing neither is 0.1. If the probability of passing the English examination is 0.75. What is the probability of passing the Hindi examination?

A card is drawn from a deck of 52 cards. Find the probability of getting an ace or a spade card.

A die is thrown twice. What is the probability that at least one of the two throws come up with the number 3?

A natural number is chosen at random from amongst first 500. What is the probability that the number so chosen is divisible by 3 or 5?