Find the mean deviation about the mean for the data 38, 70, 48, 40, 42, 55, 63, 46, 54, 44

Asked by Pragya Singh | 11 months ago |  83

1 Answer

Solution :-

First we have to find (x̅) of the given data

\( \overline{X} = \dfrac{1}{10} \displaystyle\sum_{i=1}^{10} X_i \)

\( \dfrac{500}{10}\)

= 50

So, the respective values of the deviations from mean,

i.e., xi – x̅ are, 50 – 38 = -12, 50 -70 = -20, 50 – 48 = 2, 50 – 40 = 10, 50 – 42 = 8,

50 – 55 = – 5, 50 – 63 = – 13, 50 – 46 = 4, 50 – 54 = -4, 50 – 44 = 6

-12, 20, -2, -10, -8, 5, 13, -4, 4, -6

Now absolute values of the deviations,

12, 20, 2, 10, 8, 5, 13, 4, 4, 6

\(\displaystyle\sum_{i=1}^{10} |X_i-\overline{X}| =84\)

MD = \( \dfrac{sum \;of\; deviations}{number\; of\; observations}\)

\( \dfrac{84}{10}\)

= 8.4

So, the mean deviation for the given data is 8.4.

Answered by Abhisek | 11 months ago

Related Questions

Find the mean deviation from the mean and from a median of the following distribution:

Marks 0-10 10-20 20-30 30-40 40-50
No. of students 5 8 15 16 6

 

Class 11 Maths Statistics View Answer

The age distribution of 100 life-insurance policy holders is as follows

Age (on nearest birthday) 17-19.5 20-25.5 26-35.5 36-40.5 41-50.5 51-55.5 56-60.5 61-70.5
No. of persons 5 16 12 26 14 12 6 5

 

Class 11 Maths Statistics View Answer

Compute mean deviation from mean of the following distribution:

Marks 10-20 20-30 30-40 40-50 50-60 60-70 70-80 80-90
No. of students 8 10 15 25 20 18 9 5

 

Class 11 Maths Statistics View Answer

Find the mean deviation from the mean for the following data:

Classes 95-105 105-115 115-125 125-135 135-145 145-155
Frequencies 9 13 16 26 30 12

 

Class 11 Maths Statistics View Answer

Find the mean deviation from the mean for the following data:

Classes 0-100 100-200 200-300 300-400 400-500 500-600 600-700 700-800
Frequencies 4 8 9 10 7 5 4 3

 

Class 11 Maths Statistics View Answer