Find the mean deviation about the mean for the data

 $$x_i$$ 10 30 50 70 90 $$f_i$$ 4 24 28 16 90

Asked by Abhisek | 1 year ago |  84

##### Solution :-

$$N=\displaystyle\sum_{i=1}^{5} f_i = 80$$

$$\displaystyle\sum_{i=1}^{5} f_ix_i = 4000$$

$$\overline{X} = \dfrac{1}{N} \displaystyle\sum_{i=1}^{5} f_ix_i$$

$$= \dfrac{1}{80}\times 4000=50$$

$$MD\overline{(x)} = \dfrac{1}{N} \displaystyle\sum_{i=1}^{5} f_i|x_i-\overline{x}|$$

$$= \dfrac{1}{80}\times 1280=16$$

Answered by Abhisek | 1 year ago

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