1 Answer
Solution :-
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The class interval containing Nth/2 or 50th item is 35.5 – 40.5
So, 35.5 – 40.5 is the median class.
Then,
Median = \( l +\dfrac{\dfrac{N}{2}-C}{f}× h\)
Where, l = 35.5, c = 37, f = 26, h = 5 and N = 100
Median = \( 35.5+\dfrac{50-37}{26}× 5\)
= 35.5 + 2.5
= 38
Thus, mean deviation about the median is given by
\(MD(M) = \dfrac{1}{N} \displaystyle\sum_{i=1}^{8} f_i |X_i-M|\)
= \( \dfrac{1}{100}\times 735\)
= 7.35
Answered by Pragya Singh | 1 year agoRelated Questions
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Compute mean deviation from mean of the following distribution:
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