1 Answer
Solution :-
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\( \overline{x}= A +\dfrac{\displaystyle\sum_{i=1}{f_i}u_i }{N}× h\)
Where A = 64, h = 1
So, x̅ = 64 + ((\( \dfrac{0}{100}\)) × 1)
= 64 + 0
= 64
Then, variance,
\( σ^2= \dfrac{h^2}{N^2}[N\displaystyle\sum_{i=1}{f_i}u_i^2-(\displaystyle\sum_{i=1}{f_i}u_i)^2] \)
σ2 = (\( \dfrac{1^2}{100^2}\)) [100(286) – 02]
= (\( \dfrac{1}{10000}\)) [28600 – 0]
= \( \dfrac{28600}{10000}\)
= 2.86
Hence, standard deviation = σ =\( \sqrt{2.886}\)
= 1.691
Mean = 64 and Standard Deviation = 1.691
Answered by Abhisek | 1 year agoRelated Questions
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