Find the mean and variance for the following frequency distribution.

Classes 0-30 30-60 60-90 90-120 120-150 150-180 180-210
Frequencies 2 3 5 10 3 5 2

 

 

 

Asked by Abhisek | 1 year ago |  111

1 Answer

Solution :-

 \(\overline{x}= A +\dfrac{\displaystyle\sum_{i=1}{f_i}u_i }{N}× h\)

\( 105+\dfrac{2}{30}\times 30\)

= 105 + 2 

= 107

Now Variance, 

\( σ^2= \dfrac{h^2}{N^2}[N\displaystyle\sum_{i=1}{f_i}u_i^2-(\displaystyle\sum_{i=1}{f_i}u_i)^2] \)

=  \( ( \dfrac{30^2}{30^2})[30\times 76 – (2)^2]\) 

= 2280 - 4

= 2276

Answered by Abhisek | 1 year ago

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