Evaluate the Given limit: \( \lim\limits_{x \to 1} \dfrac{4x+3}{x-2} \)
\( \lim\limits_{x \to 1} \dfrac{4x+3}{x-2} \)
= \( \dfrac{4(4)+3}{4-2} \)
= \( \dfrac{16+3}{2} \)
= \( \dfrac{19}{2} \)
Differentiate with respect to x xn loga x
Differentiate with respect to x xn tan x
Differentiate with respect to x x2 ex log x
Differentiate with respect to x x3 ex
Differentiate with respect to x x3 sin x