At x = 2, the value of the given rational function takes the form \( \dfrac{0}{0}\)
\( \lim\limits_{x \to 2} \dfrac{3x^2-x-10}{x^2-4} \)
\( \lim\limits_{x \to 2} \dfrac{(x-2)(3x+5)}{(x-2)(x+2)} \)
\( \lim\limits_{x \to 2} \dfrac{3x+5}{x+2} \)
= \( \dfrac{3(2)+5}{2+2} =\dfrac{11}{4}\)
Answered by Abhisek | 1 year ago