Evaluate the Given limit: \( \lim\limits_{x \to π} \dfrac{sin( π-x)}{ π( π-x)} \)

Asked by Abhisek | 11 months ago |  120

1 Answer

Solution :-

\( \lim\limits_{x \to π} \dfrac{sin( π-x)}{ π( π-x)} \)

It is seen that x → π ⇒ (π - x) → 0

\(\dfrac{1}{π} \lim\limits_{π-x \to 0} \dfrac{sin( π-x)}{( π-x)} \)

\( \dfrac{1}{π}\times 1\)

\( \dfrac{1}{π}\)

Answered by Pragya Singh | 11 months ago

Related Questions